Vehicle a averages 14 miles per gallon of gasoline, and vehicle b averages 36 miles per gallon of gasoline. at these rates, how many more gallons of gasoline does vehicle a need than vehicle b to make a 1,008-mile trip?

So first we need to find the amount of gallons that it would take for each vehicle to travel 1,008 miles. We can do this by multiplying and canceling units:

Vehicle A:

Vehicle B:

So we found that Vehicle A needs 72 gallons to make the trip, and Vehicle B needs 28 gallons to make the trip.

Let's find the difference:

Therefore, Vehicle A needs 44 more gallons of gasoline than Vehicle B to make the trip.

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b

12

step-by-step explanation:

12 + 5 = 17

12x2=24

24-7=17