Mrs. simms told her class to find two consecutive even integers such that twice the lesser of two intergers is 4 less than two times the greater integer

Let the two consecutive even integers be 'x' and 'x+2'.

The lesser number is 'x' and greater number is 'x+2'

Since, twice the lesser of two integers is 4 less than two times the greater integer.

therefore, 2x = 2(x+2)-4

2x = 2x +4 -4

Therefore, x =0

Hence, x+ 2 = 2

Therefore, 0 and 2 are the required consecutive even integers.

lol 2

step-by-step explanation: