Can anyone me out with this problem and me understand it a little better . (g+4)-3g=1+g

So if you look carefully at the problem, you'll notice you have the letter 'g' in multiple places.

If we treat everything to the left of the equal sign as the 'left side of the equation' and everything to the right of the equal sign as the 'right side of the equation', you'll notice the letter g shows up 2 times on the left side, and 1 time on the right side.

In order to work out what 'g' is, we need to get them all on one side. This means we have to simplify the equation a bit by combining all the g's on each side of the equation and then rearranging.

So if we have (g + 4) - 3g on the left side, we can combine g and -3g, which would give us -2g (because g - 3g = -2g). So the left side becomes -2g + 4.

Let's look at the equation again:

-2g + 4 = 1 + g

We still have a g on the right side, so we need to get rid of it and move it to the left. We do this by subtracting g from both sides (which would cancel out the g on the right because g minus g is just = 0).

So the left side becomes -2g + 4 - g (because we're subtracting g from both sides). If we combine the -2g and -g, we get -3g because -2g - g = -3g. The right side becomes just 1, because g - g = 0.

So let's look at the equation again:

-3g + 4 = 1

Let's move the 4 (by subtracting 4 on both sides) to the other side to get closer to just working out g:

-3g + 4 -4 becomes -3g on the left side, and the right side becomes 1 -4 = -3.

So our equation is:

-3g = -3

Now we just need to work out g. We can do this by dividing by -3 on both sides, as this would cancel out the -3 multiplying the g on the left.

The left side becomes -3g ÷ -3 = g. The right side becomes -3 ÷ -3 = 1.

Therefore, we're left with g = 1.

a - base

b - exponent

so,