Mathematics, 12.07.2019 13:30 rosehayden21
What is the equation of a parabola with a vertex at (10,0) and a directrix x=-2?
Answers: 1
![\bf \textit{parabola vertex form with focus point distance}\\\\\begin{array}{llll}4p(x- h)=(y- k)^2\end{array}\qquad \begin{array}{llll}vertex\ ( h, k)\\\\ p=\textit{distance from vertex to }\\\qquad \textit{ focus or directrix}\end{array}\\\\[-0.35em]\rule{34em}{0.25pt}\\\\\begin{cases}h=10\\k=0\\p=12\end{cases}\implies 4(12)(x-10)=(y-0)^2\implies 48(x-10)=y^2\\\\\\x-10=\cfrac{1}{48}y^2\implies x=\cfrac{1}{48}y^2+10](/tpl/images/0081/0893/ad4da.png)
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What is the equation of a parabola with a vertex at (10,0) and a directrix x=-2?...
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