Point a pq and r are collinear on pr and pq: pr =2/3. p is located on the origin q is located at (x, y) and r is located at (-12,0) . what are the values of x and y

The values of x and y are  8 and 0 respectively.

Explanation

As 'p' is located at (0,0) and 'r'  is located at (-12,0) , that means both 'p' and 'r' are on the x-axis.  So point 'q' will be also on the x-axis , and 'q' is located at (x,y)

So, the value of y will be 0. That means the co ordinate of point 'q' is (x, 0)

Now, using the Distance formula, length of 'pq'

and length of  'pr'  

Given that,   pq : pr =2/3

So....

Thus, the values of x and y are  8 and 0 respectively.

13875138answer:

step-by-step explanation:

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