How would you find the equation of a line that is perpendicular to y = 3x + 1 and passes through point (1, -1)?

perpendicular means the slopes of the two lines are opposite reciprocals. Since the slope of y = 3x + 1 is "3", then the opposite reciprocal slope is

Next, plug in the slope ( )and point (1, -1) into the point-slope formula: y - y₁ = m(x - x₁); where (x₁, y₁) is the point.

y - (-1) = (x - 1)

y + 1 = x +

y = x +

the answer is d

step-by-step explanation:

the answer is:

the correct option:

b.

to solve the problem, we need to remember how to operate to simplify exponential expressions using the logarithms.

we are given the equation:

then, using placing logarith with base 7 on both sides of the equation, we have:

so, rounding the obtained result to two decimal places (nearest hundreth), we have:

hence, we have that the correct option:

b.

have a nice day!