There was a total of 548 dollars collected for tickets to the school play. the adult tickets cost 6 dollars, and the student tickets cost 4 dollars. if 12 more student tickets were sold than adult tickets, find the numbers of adult and student tickets sold.

This is a systems of equations problem. To begin, we need to set up our equations.

If there was a total of 548 dollars collected, and adult tickets cost $6, and students tickets $4, this equation represents that situation.

6a + 4s = 548

The variable a stands for adult, and variable s for student. Now, if 12 more student tickets were sold than adults, this would represent that.

a + 12 = s

Now we can set it up as a systems of equations.

Because s = a + 12, we can plug that in into the other equation.

6a + 4(a + 12) = 548

Distribute 4.

6a + 4a + 48 = 548

Combine like terms.

10a + 48 = 548

Subtract 48 from both sides.

10a = 500

Divide both sides by 10.

a = 50

Plug a into the original equation.

50 + 12 = s

Combine like terms.

62 = s

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an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )