Sara draws a marble out of a bag. it is either red or green. she records the data and then puts the marble back in the bag. she repeats this process 50 times to get the following results: red: 35 green: 15 because sara knows that there are 4 marbles in the bag, she knows that the probability of choosing a red marble must be either 1/4, 2/4, 3/4, or 4/4. based on her data, which of these models is most probable? a. 1/4 b. 2/4 c. 3/4 d. 4/4

Well think about if you have 35 out of 50 you get around 1.4. Also look at the data you can tell that there is at least one green marble so then you can think that if it was half and half the numbers would be closer so then think that the only answer that make sense is 3/4. I hope this helps

3/4

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.

80x^8−68x^6+16^5−20x^4−4x^3+8x^2

hope i'm right lol