Graph the linear equation. find three points to solve the equation, then plot on the graph. -x-y=0

Multiply both sides of -x-y=0 by -1 to obtain x + y = 0, and then solve for y:

y = -x This is a straight line whose graph is much like that of y = x, except that y decreases as x increases.

We may choose any desired x values and calculate the associated y-values.

x y = -x (x,y)

0 0 (0,0)

-2 2 (-2, 2)

4 -4 (4, -4)

Plot these three points on graph paper and then draw a straight line through them all.

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

u also answered this so i think u would know but i am here to

put in or use mine