Write the equation of a line in slope intercept form that passes through the points (0, 7) and (5, 3)

first you find the slope by making using the quation for slope

(7-3)/(0-5) and you find your slope is 4/-5. Then you can plug this into point slope form using on of the coordinates so:

y-y1=m(x-x1) --> y-3=-4/5(x-5)

then you distribute the -1 so > y-3=-4/5x+4 and then move the 3 over

so the answer is y= -4/5x+7

To solve this problem, we must remember that the formula for slope, represented by the variable m, is m = y2-y1/x2-x1, and slope-intercept form is y=mx + b, where the variable m again represents the slope and the variable b represents the y-intercept. First, we will solve for the slope by plugging in the values we are given in our ordered pairs into the formula and simplifying using subtracting and then division:

m = y2-y1/x2-x1 = (7-3)/(0-5) = 4/-5 = -4/5

The y-intercept is found where the x value is equal to 0, which is given to us in the point (0,7). This means that b = 7 because the variable b represents the y-intercept.

Now, we can substitute in these values into slope-intercept form to create our equation.

y = mx + b

y = -4/5x + 7

Therefore, your answer is y = -4/5x + 7.

Hope this helps!