Simplify cube root of 7 over fifth root of 7. 7 to the power of 1 over 5 7 to the power of 8 over 15 7 to the power of 5 over 3 7 to the power of 2 over 15

So to put your equation into algebraic terms, your asking for .

Firstly, we have to convert these into fractional exponents. The rule to do that is . Applying that here, our equation is

Next, the rule with dividing exponents with the same base is to just subtract the exponents, so with this we are subtracting 1/5 from 1/3. However, we need to find their LCM, or lowest common multiple, of 3 and 5. You can do this by listing out what numbers 3 and 5 are factors of. In this case, the LCM is 15. Multiply 1/3 by 5/5 and 1/5 by 3/3:

Now that they share the same denominator, subtract the numerators of the 2 fractional exponents and your answer will be , or the last option.

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v