In a random sample of 50 undergraduate students at a college, it was found that 44 students regularly access social networking websites from their college library. what is the margin of error for the true proportion of all undergraduates who access social networking sites from their college library? a. 0.046 b. 0.038 c. 0.014 d. 0.070 e. 0.092

Option E) 0.092

Step-by-step explanation:

Given that in  a random sample of 50 undergraduate students at a college, it was found that 44 students regularly access social networking websites from their college library.

Sample size = 50

Of those students who regular access social networking websites from their college library=44

Sample proportion p =

Std error of p =

Margin of error for 95% level=1.96*0.04596

=0.09008

Approximately this equals option E) 0.092

total amount to be paid = $19.5

step-by-step explanation:

given ,

original price = $25.99

discount = 25%

discount amount = 25% of original price

discount amount = 25/100   * 25.99

discount amount = $6.49

hence , the total amount to be paid = original price - discount amount

                                                            = $25.99 - $6.49

                                                            =$19.5

total amount to be paid = $19.5