The length of a rectangle is 5 in. less than four times the width. if the diagonal is 10 in. more than the length, find the dimensions of the rectangle.

by definition, a rectangle has 90° angles so you can use the Pythagorean Theorem

width (w) = w

Length (L) = 4w - 5

Diagonal (D) = L + 10 = (4w - 5) + 10 = 4w + 5

w² + L² = D²

w² + (4w - 5)² = (4w + 5)²

w² + (16w² - 40w + 25) = (16w² + 40w + 25) expanded the squares

w² - 40w = 40w subtracted 16w² and 25 from both sides

w² - 80w = 0 subtracted 40w from both sides

w(w - 80) = 0 factored the equation

w = 0, w - 80 = 0 Zero Product Property staes to set each equal to 0

w = 0, w = 80 solved each equation

w = 80 eliminated w = 0 ... width must have a dimension!

Length (L) = 4w - 5 = 4(80) - 5 = 320 - 5 = 315

Diagonal (D) = L + 10 = (315) + 10 = 325

width=80, Length=315, Diagonal=325

y= 2x+7

changed to y= 5x +7

as slope is increased from 2 to 5

therefore it would be less steeper

so, option d) is correct