How many planes are in the figure shown

Any three non collinear points define a plane.

Here the base itself is on the plane HXBN

So that is one plane.

J, X, B are non collinear points and form the triangle JXB.

This triangle also defines a plane.

J, N , B are another triplet of non collinear points making triangle JNB.

So JNB defines the third plane.

J, H, N are three non collinera points making triangle JHN.

So JHN defines the fourth plane.

Finally J, H, X are non collinear points which make the triangle JHX.

JHX defines the fifth plane.

Hence there are 5 planes in all in the given figure.

bull

step-by-step explanation:

hello from mrbilldoesmath!

answer:   x^2 + y^2 = 1024

discussion:

the equation of a circle with center (h,k) and radius "r" is

(x-h)^2 + (y-k)^2 = r^2.

in our case

(x-0)^2 + (y-0) ^2 = 32^2 = 1024

you,

mrb