What is the equation of a line that passes through the point (3,2) and is parallel to the y-axis? a. y=3b. y=2c. x=2d. x=3

equations that aer paralell to t he y axis are x=c where c is constant

given the point (3,2), the x value is 3 and the y value is 2

since we need x=c where c is a constant, it is logical to say that the constant will be 3 since in (3,2), x=3

answer is x=3

answer is D

i think that you should ask google for the answer to that problem because if we don't know it google does

solution:

we have to construct

∠m nt ≅ ∠p qr

the steps to draw this construction are

step 1: use a compass to draw an arc from point q which intersects the side pq at point a and the side qr at point b.

step 2: draw a segment nt and use the same width of the compass to draw an arc from point n which intersects the segment nt at a point x.

step 3:

step 4: join points n and y using a straightedge.

step 3:

option (d).maintaining the same width of the compass as ab, draw an arc from point x such that it intersects the arc drawn from n in a point y.

to draw   congruent angles , 1. width of compasses while drawing two angles should be same i.e from point at which angle has to be drawn, 2.the distance between the two points where the compass intersects the two sides should be same while drawing any two congruent angles.