What is the equation of tha line , in general form, that passes through the point (1,1) and has a y-intercept of 2

The x-value at the y-intercept is 0. The y-value there is 2. As the x-value increases by 1 unit to x=1, the y-value decreases by 1 unit to y=1. Thus, the slope is -1, and the slope-intercept form of the equation can be written as

... y = -x + 2

Subtracting the right side puts the equation into general form.

... x + y - 2 = 0

x = 3 ± √(5+y)