Abc is a triangle and a=50 and angle b=angle c find angles b and c

The sum of the angles of a triangle must equal 180.

A + B + C = 180

50 + B + C = 180

B + C = 180 - 50

B + C = 130

If B and C are equal to each other, we can just divide 130 by 2 to find the other two angles.

130 / 2 = 65

Angles B and C are both 65 degrees

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?

after 1 year: 221 deer

step-by-step explanation:

30% of 170 is 51. 170+51=221