How do i find the maximum value for each function and determine which function has the largest maximum y-value?

Hey!!

f(x) = -4(x-6)^2 + 3

Maximum value is found by solving the root of the first derivative. that root is where the maximum value is.

f ' (x) = -8(x - 6) = 0.

So x = 6 and that's the maximum value. f(6) = 3

2cos(2x - π) + 4 is a trig function. The maximum value of cosine function is 1.

So the maximum value would be 2(1) + 4 = 6.

Hope this helps!

~LENA~

answer: bearing in mind that a rectangle has a perimeter of length + length + width + width.

step-by-step explanation:

p = perimeter

l = length

x=width

p = 2l + 2x

p = 2(l+x)     < ==== perimeter of the base of the box.