State the domain: g(x)=-2+the square root of (1-x). explain how i get the answer.

First of all, thanks for using parentheses. Your doing so made the problem so much clearer than it would have been otherwise.

g(x) = -2 + √(1-x).

What's the domain of this function? Focus on √(1-x). Recall that the domain of the square root function is [0, infinity); in other words, the domain consists of the set of all real numbers equal to or greater than zero (0).

What's the domain of √(1-x)?

Borrowing the comments above, (1-x) must be ≥ 0.

Let's solve this inequality: Add x to both sides. We get 1 - x + x ≥ 0 + x.

Then x ≤ 1 is the domain of the given function.

we know that

applying the law of sines

°

so

∠j=18°

∠k=29°

∠l=180-(18+29)=133°

the answer part a) is

the measure of angle k is  ≈29°

part b)  the measure of angle k could also be

(180-29)=151°

so

∠j=18°

∠k=151°

∠l=180-(18+151)=11°

the answer part b) is

the measure of angle k could also be 151°

read more on -

150.6

all i did was i multiplied 5.02 by 30