Which function in vertex form is equivalent to f(x)=x^2+8-16x?

Vertex form of the given function will be f(x) = (x - 8)² - 56

Step-by-step explanation:

Standard form of the function is given as

f(x) = x² - 16x + 8

Vertex form of the quadratic function is represented by

f(x) = (x - h)² + k

Where (h, k) is the vertex of the parabolic function..

For the function

f(x) = x² + 8 - 16x

     = [x² - 2(8x) + 8² - 8²] + 8

     = [(x - 8)²- 8²] + 8

     = [(x - 8)² - 64 + 8]

     = (x - 8)² - 56

Therefore, vertex form of the given function will be f(x) = (x - 8)² - 56

e

step-by-step explanation:

an equation by definition has to have two or more variables (x and 2 in this case)

both graphs increase on their domain

neither graph has a y-intercept

step-by-step explanation:

the following points can be visualized easily from the graph