If b is the midpoint of ac, and ac=8x-20. find bc. ab=3x-1

If B is midpoint of AC, then AB = BC and AC = AB + BC = 2AB

AC = 8x - 20, AB = 3x - 1

substitute

8x - 20 = 2(3x - 1)

8x - 20 = 6x - 2 |+20

8x = 6x + 18 |-6x

2x = 18 |:2

x = 9

BC = 3x - 1 → BC = 3(9) - 1 = 27 - 1 = 26

BC = 26

answer: the answer is one of

step-by-step explanation:   we are given to write a proper fraction where the whole is divided into an even number of equal parts less than ten, and an odd number of those parts exist.

an even number less than 10 may be one of 2, 4, 6 or 8. so, the whole may be one of these four evens.

now, an odd number of these parts must exist, so the numerator must be an odd number, one of 1, 3, 5 or 7. it cannot be 9 because then the fraction will become improper.

thus, our fraction may be one of the following

in problems involving proportions, we can use cross products to test whether two ratios are equal and form a proportion. to find the cross products of a proportion, we multiply the outer terms, called the extremes, and the middle terms, called the means.

hope it