Can you me figure out this answer? and you

Here you're being asked to find the "perimeter" of the space, even tho' the problem doesn't specifically ask for it.

The formula for P is P = 2W + 2L.

Here the width, W, is 3 1/2 yds, and the length, L, is 4 2/3 yds. Subbing these two values into the formula for P (above) results in:

P = 2(3 1/2 yds) + 2(4 2/3 yds)

= 7 yds + 9 1/3 yds = 16 1/3 yds, total.

answer: 1) twenty-seven times y

              2) twenty-seven multiplied by y

plz yuo

step-by-step explanation: