Anumber is divided by 3. then 14 is added to the quotient. the result is 33. what is the orginal number?

let "a number" = x

a number is divided by 3 => x/3

14 is added to the quotient => (x/3) + 14

The result is 33 => " = 33"

Solve for x

(x/3) + 14 = 33

Isolate the x. Note the equal sign. What you do to one side you do the other.

Subtract 14 from both sides

(x/3) + 14 (-14) = 33 (-14)

x/3 = 19

Isolate the x. Multiply 3 to both sides

x/3(3) = 19(3)

x = 19(3)

x = 57

57 is your original number

hope this helps

since proposition states that a number is greater than 25, if is true then the number must actually be greater than 25.

this implies that all possible options, except 24, can be accepted

b is the correct answer