Marquise has 200200200 meters of fencing to build a rectangular garden. the garden's area (in square meters) as a function of the garden's width www (in meters) is modeled by: a(w)=-w^2+100wa(w)=−w 2 +100wa, left parenthesis, w, right parenthesis, equals, minus, w, start superscript, 2, end superscript, plus, 100, w what is the maximum area possible?

Area a(w)= where w is the width

Area is in quadratic form.

To find maximum are we need to find the vertex.

a(w)=

To find vertex we use formula w=

a= -1 and b = 100

So w = = 50

We will get maximum area when width w= 50m

To find maximum are we plug in 50 for w and find a(50)

a(w)=

a(50)=

a(50)= -2500 + 5000

= 2500

So maximum area is 2500 square meter and the dimensions are length = 50m , width = 50m

there are 70 more legs than eyes at the dog show (196 – 126 = 70). dogs have two more legs than eyes, and humans have the same number of legs as eyes. thus 70 is twice the number of dogs at the show, so the number of dogs is half of 70, which is 35. to get the number of humans, subtract 35 from 63: 63 – 35 = 28.

step-by-step explanation: