What is the solution to this system of linear equations 2s-3c=-6

So the system is:

For this, I will be using the substitution method. So firstly, subtract 2c on both sides of the second equation:

Next, substitute s in the first equation for (11-2c) and solve for c:

Now that we know the value of c, replace c with its value and solve for s in either equation:

In short, c = 4 and s = 3.

$4

step-by-step explanation:

$30×5=$150

$150 minus $130=$20

$20÷5=$4.

hope to and hope that my answer is brainliest.(follow me )

d) by the cross product property, ab^2 = bc multiplied by ad

step-by-step explanation:

we are given

in the given triangle abc

angle a is 90° and segment ad is perpendicular to segment bc

we can see that

triangle(abc) and triangle(abd) are similar because they have common side and same angle (90 degree)

so, triangles(abc) and abd are similar

since, they are similar

so, the ratio of their sides must be equal

we get

now, we can cross multiply

and we get

so, this could be step to prove it