The equation of a circle is x^2+y^2-12y+27=0 what is the equation in graphing form a) (x-6)^2+(y-6)^2=27 b) (x-6)^2+y^29 c) x^2+(y+6)^2=9 d) x^2+(y-6)^2=9

The equation in graphing form:

Use:

d) x^2+(y-6)^2=9

the correct answer option is (2x-3)(2x+3).

step-by-step explanation:

we are given the following expression and we are to factorize it:

we are to find such factors that when multiplied they give a result of 36 (9 x 4 = 36) and when added they give a result of 0.

the two such factors of 36 are negative six and postive six.

factorizing the given expression to get:

therefore, the correct factorization of is (2x-3)(2x+3).

i think it’s a i believe