One number is 7 more than another number. the sum of the numbers is 63. what is one of the numbers

let one number = x, let another number = y

x = y + 7 , x + y = 63

Plug in y + 7 for x

(y + 7) + y = 63

Simplify

2y + 7 = 63

Isolate the y. Note the equal sign. What you do to one side you do to the other

2y + 7 (-7) = 63 (-7)

2y = 56

2y/2 = 56/2

y = 28

As you are only asking for one of the numbers, 28 is your answer. The other is 35.

hope this helps

correct answer is infinitely many solutions

step-by-step explanation:

2(2x + 3) = -4 + 2(2x + 5)

solving the above equation:

4x + 6 = -4 +4x +10

combining like terms

4x -4x = -4+10-6

0=0

since both sides are 0=0, we end up into true statement it means it has infinite many solutions.

so correct answer is infinitely many solutions