Assuming the conditions regarding the motion represented in the graph remain the same, determine the acceleration of the object at t=200 s. what is the instantaneous acceleration at t= 10s

Option a

Step-by-step explanation:

Given is the graph showing the relation between time and velocity.

Velocity is shown on y axis, time on x axis.

The graph shows that relation is linear with constant slope

To find equation we see that y intercept is 4,

Two points are (0,4) and (10,10)

Slope=

So equation for v is

v=0.6t+4

Now to find acceleration we can find derivative of v

For one unit change in t, v changes by 0.6 m

In other words, rate of change of velocity =

acceleration = 0.6 m/sec^2

Since acceleration is independent of t, we get

for t =10 s also

acceleration =0.6m/sec^2

OPtion a is right

the answer is d

the answer is in the first quadrant, which make the y-int positive.

since the dots are going down, therefore the correlation is negative

i hope it is right.

me! what did you put for this question?

step-by-step explanation: