Can someone answer these two questions ? a dog runs from point o to b. the dog reaches a at 2.3 s into the sprint. then the dog reaches c at 4.1 s. what is the average velocity of the dog from a to c? a test car travels in a straight line along the -axis. the graph in the figure shows the car’s position as a function of time. at which point is the velocity zero? will give brainliest

dog

Average velocity is given by the change in position divided by the time required for that change.

v = ∆x/∆t = (4 m)/(4.1 s -2.3 s) = 4/1.8 m/s ≈ 2.2 m/s

car

The instantaneous velocity is zero where the graph is horizontal (no change in position while time marches on—zero slope). Marked points C and G are such points. The appropriate choice is point C.

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step-by-step explanation: vsfdvsfvd

answer:

125 yards

explanation:

75+50=125. that is my answer