Four year ago, norma was three times as old as her daughter. six years from now she will be twice as old as her daughter. find the present age of norma and her daughter

Let’s say that the present age ofNorma’s daughter is ‘x’ years. Then 4 years ago, her age was (x - 4) years. Therefore, Norma’s age 4 years ago was: (x - 4) + 3(x - 4) = 4(x - 4) years. 6 years from now, the daughter’s age will be (x + 6) years, and Norma’s age will be: 2(x + 6) years.

Now, 6 years from now will be (6+4), i.e., 10 years away from 4 years ago. Thus, Norma’s age 6 years from now can also be written as 4(x - 4) + 10 = (4x - 6) years. Therefore, 2(x + 6) = 4x - 6.

Or, 2x + 12 = 4x - 6.

Or, 2x = 18.

Thus, the daughter’s age (x) = 9 years, and Norma’s present age = 4(x - 4) + 4 = 24 years.

i think the answer is .36

step-by-step explanation:

what i did was only 2.88 divided by 8