Graph or explain how to graph the equation: y = 3x -5

slope intercept form is

y=mx+b

where m is the slope and b is the y intercept

the equation is given in slope intercept form so that the

slope = 3

y-intercept = -5

to graph this you will first place a point on (-5,0) since it's the y intercept.

then since the slope is rise/run and we have 3 (or 3/1) you will start at (-5,0), and from there go up 3 units and to the right one unit. where you end up will be your second point.

hope this helps

there are lots of ways.   pick's theorem tells us if the vertices are lattice points the area a is

a = b/2 + i - 1

where b is the number of boundary lattice points and i is the number of interior lattice points.

in the figure i count b=16, i=50 so

a = 8 + 50 - 1 = 57

let's try the shoelace formula.   the area is half the sum of the cross products of the sides.  

a(-2,6)   -2(2)-6(-5) = 26

b(-5,2)   -5(-3) - 2(-2) = 19

c(-2,-3) -2(-3) - (-3)(4) = 18

d(4,-3)   4(3) - (-3)(5) = 27

e(5,3)   5(3) - 3(1) = 12

f(1,3)     1(6) - 3(-2) = 12

a(-2,6)

each of the cross products is twice the area of the triangle with the associated side and one vertex the origin. so the area of abo=26/2=13.

area = (1/2) (26 + 19 +   18 + 27 + 12 + 12) = 57

that checks!