What is the slope of a line that is perpendicular to the line whose equation is 7x−3y=10 7 x − 3 y = 10 ? a. −37

The perpendicular line will have a slope of -3/7.

To find this, we first have to solve our equation for slope intercept form.

7x - 3y = 10 > subtract 7x

-3y = -7x + 10 > divide by -3

y = 7/3x - 10/3.

So we know the slope of this equation to be 7/3. Since perpendicular lines have opposite and reciprocal slopes, we know we can simply flip the fraction and make it a negative to get the new slope of -3/7.

y=−9/2x+10

step-by-step explanation:

let's solve for y.

0−9x−2y=−20

step 1: add 9x to both sides.

−9x−2y+9x=−20+9x

−2y=9x−20

step 2: divide both sides by -2.

−2y

−2

=

9x−20

−2

y=

−9

2

x+10

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step-by-step explanation:

sorry no step by step