Mr. albano wants to paint menus on the wall of his cafe in chalkboard paint. the gray area below shows where the rectangular menus will be. each menu will measure 6ft wide and 7 1/2 ft tall. how many square feet of menu space will mr. albano have? what is the area of wall space that is not covered by the chalkboard paint?

Given:

Whole wall is 13 2/3 ft by 25ft

4 menus (gray areas) with measurements of 6 ft wide and 7 1/2 ft tall.

Convert mixed fractions into improper fractions.

13 2/3 ft = ((13*3)+2)/3 = 41/3

Area of the Wall = 41/3 ft * 25 ft = (41*25)/3 = 1025/3 ft² = 341 2/3 ft²

7 1/2 ft = ((7*2)+1)/2 = 15/2

Area of the menu = 15/2 ft * 6 ft = (15*6)/2 = 90/2 = 45 ft²

45 ft² x 4 menus = 180 ft²

Area of wall space not covered by the chalkboard paint:

A = 341 2/3 ft² - 180 ft² = 161 2/3 ft²

Step-by-step explanation:

please mark this answer as the brainlest

tickets for the harlem globetrotters

show at michigan state university in

2010 cost $16, $23, or, for vip seats, $40.

total revenue = 16x + 23y + 40z

if 9 times as many $16 tickets were sold

as vip tickets,

x = 9z => x – 9z = 0, if 9 times as many $16 tickets were sold

as vip tickets,

x = 9z => x – 9z = 0, sales of all three kinds of tickets would

total $46,575.

16x + 23y + 40z = 46575, how many of each kind of ticket would

have been sold?

solve for x, y and z

x − 9z = 0

x − y − z = 55

16x + 23y + 40z = 46575

x = 1170

y = 985

z = 130

welcome!

students group

step-by-step explanation:

a person who   joins a party or a seminar can explain his feelings about that particular occasion better more than anyone else.

as bella managed a show for the students in the school and invited students to watch that show

hence

students group will be the best group to survey to find this information