Atrain ticket has a perimeter of 72 centimeters and an area of 315 square centimeters. what are the dimensions of the ticket?

You can work out the perimeter by working out the sum of twice the length (l) and twice the width (w).

2l + 2w = 72

The area is length (l) * width (w)

l * w = 315.

Now we just need to do some rearrangement and isolate one of the terms so we can substitute it back into the area equation.

2l + 2w = 72

2l = 72 - 2w

l = 36 - w

l * w = 315

(36 - w) * w = 315

36w - w² = 315

w² - 36w + 315 = 0

(w - 21)(w + 15) = 0

w = -15 cannot be right, because it can't be negative, so w = 21.

Now that we know the width is 21, we can substitute it into the perimeter equation to work out the length.

2l + 2w = 72

2l + 2(21) = 72

2l + 42 = 72

2l = 72 - 42

2l = 30

l = 15.

Therefore, the width is 21 cm and the length is 15 cm.

ca = ec

cpctc makes it so that corresponding parts of the triangle you proved to be equal are equal, the other options aren't part of the part of the triangles you proved to be equal.