Write the equation of a line in slope-intercept form from the graph below.

It can bee seen easily that given line is intersecting x axis at ( 1,0) and it is intersecting y axis at (0,1)

so this line is passing through two points ( 0,1) and ( 1,0)

let us try finding the slope of this line

we know when a line passes through ( x1,y1) and ( x2, y2) the slope is :

( y2- y1) divde by ( x2-x1)

here x1 = 1 y1 = 0 and x2 = 0 y2 = 1

the slope is : m = ( 1-0) divde by ( 0-1) = 1 divide by -1 = -1

the y intercept is : b = ( where it intersect y axis ) so b=1

Equation of the line whose slope is m and y intercept is b :

Y= mx+ b

let us plug the values o f m and b

Y= -1x + 1

Or we can write it : y = -x + 1 this is the required equation of line in slope intercept form .

dalila is incorrect. the whisker on the left is very long, going all the way out to 5. the whisker goes from 5 to 30, so it has a spread of 25. the rest of the box plot values are closer together, so 5 is an outlier

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step-by-step explanation: