Antoine has $18.20 to spend on some oranges and a pumpkin. oranges cost $1.30 per pound, and a pumpkin costs $5.20. the inequality 1.30x + 5.20 ≤ 18.20 models this situation, where x is the number of pounds of oranges. solve the inequality. how many pounds of oranges can antoine buy?

Hi!

To solve this inequality, we have to isolate x on one side. Whatever we do to the equation we have to do it on both sides.

1.30x + 5.20 ≤ 18.20

Subtract 5.20 from both sides.

1.30x + 5.20 - 5.20 ≤ 18.20 - 5.20

1.30x ≤ 13

Divide by 1.30 on both sides.

1.30x/1.30 ≤ 13/1.30

x ≤ 10

Antoine can buy 10 pounds of oranges.

Hope this helps! :)

Antoine can buy 10 pounds of oranges or less!!!

4.6875 pounds

step-by-step explanation:

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation: