Ron finley is a gardener who decided a few years ago to plant several gardens in south central los angeles. he wants his next garden to be a rectangle where the length is three times the width. additionally, it must have a perimeter of 24 yards because of space constraints. what are the length and the width of the garden?

Well, we can be sure that whatever the width is, we can call it ' W '. Then, from information in the question, the length of the garden is ' 3W '.

Now, the perimeter of a rectangle is (length + width + length + width). Using the fancy algebra labels I just gave them, that's (3W + W + 3W + W). And now I can go through that, add up all the Ws, and get a total of 8W for the perimeter.

But he question tells us that the perimeter is 24 yards, so 8W = 24 yds.

Divide each side of that equation by 8, and we discover that W = 3 yds. And if THAT's true, then 3W = 9 yds. Bada bing ! We have the dimensions of the garden.

It's 3 yards wide and 9 yards long.

7

step-by-step explanation:

step-by-step explanation:   divide the numerator by the denominator to get the decimal

it would still be 193

if divide by 100 then 1.93

i am not sure