The function f(x) = x2 + 10x - 3 writers in vertex form is f(x) = (x + 5)2 - 28. what are the coordinates of the vertex?

General formula of the parabola in vertex form is

f(x) =(x-h)² +k, where (h,k) is a vertex of the parabola.

f(x) = (x + 5)²- 28

h= -5, k = -28,

so (-5, -28) is a vertex of the given parabola.

Answer is A.

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.

560

step-by-step explanation:

giggidy