The length of a rectangle is 13 centimeters less than five times its width. its area is 28 square centimeters. find the dimensions of the rectangle. the width is nothing ▼ and the length is nothing ▼

we have given that length of a rectangle is 13 cm less that five times its width.

where l is length and b is width.

we need to set up an equation according to the problem statement.

l=5b-13

we have area =28cm^2

we know that l*b=28

(5b-13)*b=28

5b^2-13b-28=0

we need to solve it by formula

we get (5b-20)(5b+7)=0

b=4 and b=-7/5 so negative value cannot be chosen so b=4

and l=5b-13=20-13=7.

l=7

i cant see the graph

step-by-step explanation:

  y= -3x is the required function.

step-by-step explanation:

we have been given a table:

x             y

0             0

1             -3

3             -9

-2             6

we can see that the values of y is -3 times the value of x

hence, the function would be: y= -3x.

put the values of x will give the same y as in the table that means function is satisfying the given table.