The angle measure of thre angle of a triangle are p, q and r. angle measure of q is one third of p and r is the difference of p and q.

In this question, i think we have to determine all the three angles of a triangle.

Since the three angles of a triangle are p,q and r.

Since, angle measure of q is one third of p, which implies

Angle measure of r is the difference of p and q, which implies

(Equation 1)

By using the angle sum property of a triangle which states that the sum of all the angles of a triangle is

p+q+r=

Substituting the value of r from Equation 1,

p+q+p-q=

2p=

p=

Since

Since, r=p-q

r =

The angle measure of three angle of a triangle are p, q and r.

As, sum of angles of triangle is 180 degrees.

So, p+q+r=180

Angle measure of q is one third of p

q=p

r is the difference of p and q

r=p-q

As, q=

So, r=p-q=p-

r=

r=

r=

As, p+q+r=180 and q= and r=

So, we get

p++=180

To get rid of fraction, let us multiply the complete equation by 3

3*p+ 3* + 3*=3*180

3p+p+2p=540

6p=540

To solve for p, let us divide by 6 on both sides

p=90

As, p=90

So, q=

q=

q=30

And, r=

r=

r=

r=60

So, p=90, q=30, r=60

The three angles of triangle are 90,30 and 60

the answer to this question is in the pic

c

step-by-step explanation:

at least i think its