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Mathematics, 14.07.2019 01:30 shadowblade8203
An unusual number cube (with 6 sides) has the numbers 2, 2, 4, 4, 6, and 6 on its faces. it is rolled once. match the outcome to its probability. 1. p(2 or 4) 1 2. p(multiple of 2) 2/3 3. p(multiple of 3) 1/3 4. p(odd prime numbers) 0
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Mathematics, 22.06.2019 01:10
Evaluate 8x2 + 9x − 1 2x3 + 3x2 − 2x dx. solution since the degree of the numerator is less than the degree of the denominator, we don't need to divide. we factor the denominator as 2x3 + 3x2 − 2x = x(2x2 + 3x − 2) = x(2x − 1)(x + 2). since the denominator has three distinct linear factors, the partial fraction decomposition of the integrand has the form†8x2 + 9x − 1 x(2x − 1)(x + 2) = correct: your answer is correct. to determine the values of a, b, and c, we multiply both sides of this equation by the product of the denominators, x(2x − 1)(x + 2), obtaining 8x2 + 9x − 1 = a correct: your answer is correct. (x + 2) + bx(x + 2) + cx(2x − 1).
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An unusual number cube (with 6 sides) has the numbers 2, 2, 4, 4, 6, and 6 on its faces. it is rolle...
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