Find the solution of 5 times the square root of the quantity of x plus 7 equals negative 10, and determine if it is an extraneous solution a) x = −3; extraneous b) x = −3; not extraneous c) x = 11; extraneous d) x = 11; not extraneous

I took the test its x=-3; extraneous

Step-by-step explanation:

The given equation is

Squaring on both the sides of the equation, we get

x = -3

An extraneous solution is a root of a transformed equation but it is not a root of the original equation.

Here x= -3 is also a root of the transformed equation but it is not a root of the original equation as we can see in the given equation

As we put x = -3 in left hand side of the equation , we get

which is not equal to -10 that is the right hand side of the equation.

Therefore, x = -3 is an extraneous solution to the given equation.

So, Option B is the correct answer.

y + 11 = (1/4)(x + 16)

step-by-step explanation:

what chart am i supposed to follow?