2x + 5y = 34 x + 2y = 14 a. x = -26, y = 20 b. x = 2, y = 6 c. x = 3, y = 5.5 d. x = 10, y = 2

2x+5y=34(1)

x+2y=14

x=14-2y(2)

substitute value of x from (2) in (1)

2(14-2y)+5y=34

distribute 2 over the bracket

28-4y+5y=34

28+y=34

y=34-28

y=6

plugging this y in second equation to get x

x=14-2y

x=14-2(6)

x=2

answer x=2, y=6

just take the area of the square and then the area of the circle then subtract the circle area from the squares area

step-by-step explanation:

2(2x + 3) = -4 + 2(2x + 5)

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 6

4x - 6 + 6 = 4x - 6 + 6

4x = 4x

x = x

unlimited solutions.