Find the axis of symmetry for this parabola: y= -x^2-2x-5

Given the equation of parabola: y = -x² - 2x - 5

y = ax² + bx + c and negative value of 'a' tell us that it is a downward open parabola whose axis of symmetry would be x = k.

where k is the x-coordinate of vertex of given parabola.

Finding the vertex of parabola, x =

So, the axis of symmetry for this parabola is x = -1.

d

step-by-step explanation:

by observation, we can see that the the graph is simply the graph of y = |x| that has been shifted 4 units downwards and 3 units to the left.

we can recognize in choice d :

y = | x + 3 |   - 4 (rewriting in general form)

y = | x - (- 3) |   - 4

the "-4 " term means   that the graph has been shifted by 4 units in the negative y direction

the "-3 " term means   that the graph has been shifted by 3 units in the negative x direction

this matches our observation of the graph described above.

it could be 1,3 and more others to create a cylinder.

step-by-step explanation: