Taxes on the property buyer tamara is purchasing are $8,200, due on december 31. if the closing is set for june 29th, using the 365-day method, how much of the taxes will be credited to the buyer? (assume it is not a leap year and the day of closing belongs to the seller.) $4,044 $4,178 $4,077 $4,

The buyer will be paying taxes for 185 days, so will pay

... (185/365)·$8200 = $4156

Your most appropriate choice seems to be $4178, which corresponds to 186 days' taxes.

There are 30 days in each month in the last half of the year, plus 1 additional day in each of July, August, October, and December. The 30th of June also belongs to the buyer (but the 29th, closing day, does not), so there are 180+5 = 185 days for which the buyer must pay taxes. The answer choices don't include that value.

answer: ratio of volume of cone (with 3 times the height and equal diameter) to volume of cylinder is 2 to 1. the value of π is not used.

step-by-step explanation:

radius is diameter/2 = 4.

area of circle is π r^2.

volume of cylinder is height × area of base = hπr^2 = 3(4^2) π = 48π cubic inches.

not knowing the formula for volume of cone, i calculate it using calculus (which is for calculating things).

volume of cone is integral 0 to h area(y) dy. area(y) is π r(y)^2. r(y) runs r to zero as y runs zero to h, r(0) = r, r(h) = 0.

r(y) = r - r/h y

area(y) = π (r - r/h y)^2 = π (r^2 - 2r^2y/h + r^2y^2/h^2) = π r^2(1-2y/h+y^2/h^2)

antiderivative area(y) = π r^2 (y-y^2/h+y^3/(3h^2))

integral 0 to h = π r^2(h-h^2/h+h^3/(3h^2) - (0)) = π r^2(h - h + h/3) = π r^2(h/3) = π/3 r^2 h

volume of this cone is π/3(4^2)18 cubic inches.

= 6 16 π = 96π cubic inches.

cone has twice the volume, 96/48.

cone height is 6 times the cylinder.

ratio of volume formula: π r^2 cancels.

cone over cylinder ratio is 6h/3 to h, 2 to 1.

= 5

step-by-step explanation:

to find the 15th term substitute n = 15 into the nth term formula

= (- 3 × 15 ) + 50 = - 45 + 50 = 5