Atest has two parts, a and b, each containing 10 questions. a student needs to choose 8 questions from part a and 4 questions from part b. in how many ways can he do that?

Part A number of combinations of 8 from 10 = 10C8 = 10C2

= 10*9 / 2 = 45

Part B Number combinations = 10C4 = (10*9*8*7)/ (4*3*2) = 210

Total number of ways = 45 * 210 = 9450 (answer)

150.6

all i did was i multiplied 5.02 by 30