Find the percent of change from 83 gallons to 25 gallons. round to the nearest tenth of a percent if necessary.

Alright, lets get started.

The initial value = 83 gallons

The last value = 25 gallons

The change in value = 83 - 25

The change in value = 58 gallons

We need to find the change in percent

The formula for percent = change / initial value * 100

So, the percent change = 58 / 83 * 100

So, the percent change = 69.8795 %

Rounding to nearest tenth

the percent change = 69.9 % : Answer

Hope it will help :)

d. 24+-0.114

step-by-step explanation:

the question requires us to calculate the approximate 95% confidence interval for the mean number of ounces of ketchup per bottle in the sample given the following statistics;

sample mean = 24

standard deviation, σ = 0.4

sample size , n = 49

the confidence interval for a population mean is calculated using the formula;

sample mean ± z-score*(σ/sqrt(n))

the z-score associated with a 95% confidence interval, from the standard normal tables, is;

1.96

substituting these values into the formula;

24 ± 1.96*(0.4/7)

= 24 ± 0.112

from the alternatives given, choice d is closest to the above expression;