State the possible number of positive real zeros, negative real zeros, and imaginary zeros f(x)=-x^3-x^2+14x-24

Examine the number of sign changes for f(x) and f(-x)

There are two sign changes for the coefficient of f(x), so the function has 2 or 0 positive real zeros.

There is 1 sign change for the coefficients of f(-x). So f(x) has one negative real zero.

Thus, f(x) has 2 or 0 positive real zeros, 1 negative real zero, 2 or 4 imaginary zeros

38.5

step-by-step explanation:

lets say, first number = r

second number = 3r+7

total = 49

(r)+(3r+7)= 49

4r+7 = 49

4r = 42

r = 42/4

r= 10.5

3r+7 = 3(10.5)+7 = 38.5

hope this

32/80  

91/140

the last one 54 doesn't go into 45. 54/100 ?

step-by-step explanation: