Aconstruction crew must build 3 miles of road in one week. on monday, they build 2/3 mile of road. on tuesday, they build 1/4 mile of a road. how many miles of road do they still have to build thus week?

So first we need to find how much road they have built already this week (on Monday and Tuesday).

We are told that Monday they built mile and on Tuesday they built mile. So let's add them together. We'll use a denominator of 12, since that is a common factor to both of them. What you do to the bottom of the fraction you must do to the top:

So now that we have a common denominator, we can add them together:

They built mile of road so far this week. If they need to build 3, we need to subtract from 3 to find how much remains. Let's get 3 to a number of 12 so we have a common denominator:

Now let's subtract:

So now we know that the amount of road left that they must build this week is mile.

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

step-by-step explanation:

given   that triangle lno is congruent to triangle lnm.

we have to fill up the blanks in the given question.

according to above order of congruency   kept in mind we can say that

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

ln ≅ ln due to common in both.

hence, by sas congruency,

the side angle side rule   states that if two sides and the included angle of one triangle are congruent to another triangle, then these two triangles are congruent.