Asubmarine cuts through the water at an elevation of 203 meters under the sea. the sub rises, and the elevation changes by 4.3 meters per minute for the first 15 minutes. the sub continues to rise at 5.2 meters per minute for the next 12 minutes. what is the elevation of the submarine after rising? assume that sea level is at an elevation of 0 feet. a. -126.9 m b. -76.1 m c. 126.9 m d. 339.9 m

The 1st 15 minutes it went up by: 15 x 4.3 = 64.5 m

-The 2nd 12 minutes it went up by :12 x 5.2 = 62.4 m

After 27 minutes it went up by 64.5+32.4 = 126.9

So its new elevation is 203-126.9 = 76.1

The answer is -76.1 meters.

The submarine elevation before rising is -203 meters (it is negative because it is under the sea level which has 0 elevation): d₁ = -203 m

After the first rising, it moved 64.5 m: l₁ = 4.3 · 15 = 64.5 m

After the second rising, it moved 62.4 m: l₂ = 5.2 · 12 = 62.4 m

So, to calculate the elevation of the submarine after rising (d₂), we will add (because it is not going deeper, it rises toward the elevation of 0) two movements to the elevation before rising:

d₂ = d₁ - (l₁ + l₂) = -203 + (64.5 + 62.4) = -203 + 126.9 = -203 + 126.9 = -76.1.

sine

step-by-step explanation:

the answer would be 484

step-by-step explanation:

just multiply 0.484 times 1,000 (formula)